if 2^x -3x +1 = a(x-1)^2 + b(x-1)+c find the values of a, b and c
Are you sure it is supposed to be 2^x?
oopss my apologies, its meant to be 2x^2
Expand right side of the equation, then equate coefficients of both expressions. You ok with this?
@ stroodle, would you be kind enough to show me the working out?
If: 2x^2-3x+1=a(x-1)^2 + b(x-1)+c Make both equations equal to 0, when you do that they will be both equal to eachother. 2x^2-3x+1=0 a(x-1)^2+b(x-1)+c=0 Now you can solve the first equation. x = 1 or x=1/2 Now you can substitute your x into that equation.. I'm not sure what to do from here.. but hopefully this helps. I might be wrong though.
brb. I'll post another solution in 10-15mins if no-one else does.
You have four unknowns, you will need to somehow create for individual equations from that equation and solve them simultaneously. Possibly.
umm thanks chaise. lets wait and see how stroodle does it! stroodle your input is highly anticipated!
if you expand rearrange the right side of the equation you should get: \[ax^2+(b-2a)x+a+c-b\] So now you can equate the coefficients of the two sides of the equation. i.e. a=2 b-2a=-3 a+c-b=1
Let me know if you don't get it.
why thank you @ stroodle i fully understand, thank you math whiz!
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