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An 18-foot pole is leaning against a wall. It touches the wall 16 feet above the ground. Find the measure of the angle that the pole makes with the ground. Round your answer to the nearest degree.
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\[180-90-cos^{-1}(\frac{16}{18})\] As there's 180 degrees in a triangle, and the wall is probably at a right angle to the ground.
Actually, you can just do: \[sin^{-1}(\frac{16}{18})\] Sorry, haven't done trig in a while..
sinθ = 16/18 = 8/9 θ = arcsin(8/9) = 62.73° θ = 63°
\[\sin^{-1}(\frac{8}{9})\] what stroodle said
also what mathematicalpro said 62.7339555...
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