Question

can someone not only give me the answer to this problem but also show me how you got it? A surveyor is standing 120 meters from the base of a tower. He determines that the angle of elevation (the angle formed by the ground and the surveyor’s line of sight to the top of the tower) is 30 degrees. The surveyor’s eye level is 1.7 meters above the ground. Find the height of the tower.

Answer 1

Chris, do you have answers to choose from?

Answer 2

no

Answer 3

Using the tanget property based on the information you will have tan(theta)=opp/adj...this will be tan(30)(120)=opp=69.282...then add the height for the surveyo's eye level and the final answer is...69.282+1.7=70.982meters

Answer 4

thank u =)