Question

ok i am stuck on this steps 1/6[(ln4)-(ln3)] please help me solve thanks

Answer 1

thats the question?

Answer 2

it to evaluate integral..
http://www.webassign.net/cgi-bin/symimage.cgi?expr=int_%283%29%5E%284%29%201%2F%286%20x%29%20dx

Answer 3

thats right, do u know the rules of logarithms?

Answer 4

nope i was hoping you could help me out with where i got up to

Answer 5

ln is the natural log right?

so when u have lnx-lny
u can write it as ln(x/y)

Answer 6

so this is 1/6 ln(4/3)

Answer 7

1) log(mn) = log(m) + log(n)

2) log(m/n) = log(m) – log(n)

3) log(m^n) = n · log(m)

Answer 8

ok so when i multiply how do i do that?

Answer 9

im sorry but multiply what?

Answer 10

1/6 ln (4/3) or is thats it?

Answer 11

if u mean the answer
is
( 1/6) * ln(4/3)
on the calculator
or u just leave it like that
coz ln(4/3) is anumber

u cn write it as ln(4/3) / 6