Stefan left school and traveled toward his
friend's house. Eugene left two hours later
traveling at 40 km/h in an effort to catch up
to Stefan. After traveling for three hours
Eugene finally caught up. What was
Stefan's average speed?
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OpenStudy (anonymous):
need help
OpenStudy (anonymous):
Ok, ready to work toghether?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Ok.
First Stefan leaves right?
Then 2 hours pass by, then Eugene goes
drives for 3 hours.
If his velocity is 40 km/h and he drove 4 hours, how many Km did he travel?
OpenStudy (anonymous):
sorry, he drove 3 hours
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
160
OpenStudy (anonymous):
120 for 3 hour
OpenStudy (anonymous):
actually 120
V=d/t
d=V*t
d= 40*3=120
OpenStudy (anonymous):
ok, so if both of them started at the same place, we know they travelled the same distance
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OpenStudy (anonymous):
correct?
OpenStudy (anonymous):
so Stefan's average speed is 40km/h?
OpenStudy (anonymous):
So, the total time since stefan started the trip, is the first 2 hours plus the 3 hours eugene drove afterwards for a total of 5 hours
OpenStudy (anonymous):
using the formula
V= distance / time
V= 120 km / 5 hours
V= ?
OpenStudy (anonymous):
24
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