Question

Can someone help me pleae?

Answer 1

\[(-64)^{-4/3} \]

Answer 2

\[1/\sqrt[4]{(-64)^{3}}\]

find the least common multiples? not sure on the term here, but split 64 up into small numbers, like 2's and 3's. so 64 = 2*2*2*2*2*2 or 2^6
so (2^6)^3 means that there are 6*3 or 18 2's under the radical. The negative will stay because a negative *negative*negative = negative
now you have a -(2^18) under the radical.

Answer 3

Can you solve this from here?

Answer 4

if you cannot the trick to solve this problem is to take out pairs of numbers and square root them; when you square root them the value is put outside the radical.

Answer 5

since there is a 4, not a 2 on the radical, you need to take out pairs of 4 numbers. take the 4th root of that larger number and place it outside the radical.

Answer 6

so here we go:\[1/\sqrt[4]{(-64)^{3}} = 1/\sqrt[4]{(-1)^{3}2^{18}}\]

Answer 7

so since there are only 3 -1's it stays under the radical, but there are 18 2's, so you could take 4 pairs of 4 2's. This means you can isolate 2*2*2*2; 2*2*2*2; 2*2*2*2; 2*2*2*2 and take them out of the radical after taking the 4th root of each set. All this means is from each pair of 4 2's cross out 3 of them and leave one outside of the radical. Your answer should reduce to this:

Answer 8

\[1/(16\sqrt[4]{-4})\]

Answer 9

Good luck!