Question

In Triangle ABC, Cos B = (9/12) .....find Sin B.

Answer 15/9
12/9
7.94/12

9/12

Answer 1

note that cos^2 B + sin^2 B = 1

Answer 2

7.94/12

Answer 3

\[opposite=\sqrt{12^2-9^2}\]\[\sqrt{144-81}\]
=7.937
sinB =7.937/12

Answer 4

Don't think that we need a diagram buddy

Answer 5

u cud instead use cosB^2 + sinB^2 =1. . .sinB= sqrt(1-(9/12)^2)))

Answer 6

\[\sin x=\sqrt{1-(9/12)^2} \sin x=\sqrt{144-81/144} sinx =\sqrt{63/144} sinx=\sqrt{0.43}\]