Mathematics
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OpenStudy (anonymous):
write the standard form of equation of the line decribe.
through:(2,0), parallel to y=2/3x
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OpenStudy (anonymous):
need you help
OpenStudy (aroub):
okay parallel lines have same slope , m=2/3x , (2,0) y=mx+b, 0=2/3(2) +b
0=4/3+b,3/3+4/3 =b , 7/3=b so, y=2/3x+7/3
OpenStudy (aroub):
the answer is y=2/3x+7/3
OpenStudy (anonymous):
ok thank you
OpenStudy (aroub):
ANYTIME! :D
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OpenStudy (anonymous):
so you use formular y=mx+b?
OpenStudy (aroub):
YES
OpenStudy (aroub):
u can also use another formula
OpenStudy (aroub):
but i prefer to use y=mx+b
OpenStudy (anonymous):
what formular can be if you don't use last one?
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OpenStudy (aroub):
ah sorry i really forgot how to use bec. i really dont use it but wait illl check in my book
OpenStudy (aroub):
if i find that book , im really sorry
OpenStudy (anonymous):
but its result is 2x-3y=4
OpenStudy (aroub):
okay my sis told me its y-1=m(x1-x1)
OpenStudy (aroub):
sorry y-y1=m(x-x1)
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OpenStudy (aroub):
oh yes sry i just checked my answer its wrong its supposed to be y=3/2x-4/3
OpenStudy (anonymous):
what isvalue of m of this case
OpenStudy (aroub):
oh and 2x-3y=4 is the same as y=2/3x-4/3
OpenStudy (aroub):
m is the slope
OpenStudy (anonymous):
m =2/3 x?
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OpenStudy (aroub):
2/3 without the x
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
if you use y-y1=m(x-x1, its equation is ?
OpenStudy (anonymous):
y1=0?
OpenStudy (anonymous):
x1=2?
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OpenStudy (aroub):
same thing its just other equation to use exactly the same answer as the y=mx+b
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
can you help me other one?
OpenStudy (aroub):
yes but its very slow in here wanna go to twiddla??
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OpenStudy (anonymous):
throught:(-2,4), parallel to y=-3/2y +3
OpenStudy (anonymous):
ok thanks