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Mathematics 17 Online
OpenStudy (anonymous):

Use the binomial coefficient formula to calculate the binomial coefficient for the 7th term in a polynomial expansion when the power of the binomial is 8.

OpenStudy (anonymous):

i need help under standing the problem...i dont get it

OpenStudy (anonymous):

binomial coefficient refers to the constant in front of the term ryt?

OpenStudy (anonymous):

i dont know

OpenStudy (anonymous):

ok let me teach this binomial stuff to u so that u cn confidently tackle the others on ur own hpefully

OpenStudy (anonymous):

if u hav (x+a)^2 what is the expansion?

OpenStudy (anonymous):

i dont know...

OpenStudy (anonymous):

x^2 +2ax + a^2

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

do u knw hw i gt that answer?

OpenStudy (anonymous):

distribute but i dont know

OpenStudy (anonymous):

ok. do u see that the powers of x is decreasing in each term?

OpenStudy (anonymous):

sure...

OpenStudy (anonymous):

it goes x^2 then x^1 then x^0...power decreases all the time

OpenStudy (anonymous):

ok ya

OpenStudy (anonymous):

do u see that a's power increases all the time?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

now thats a pattern and thats how the terms are formed.now we need to find out hw the numbers in front of the terms are formed. but just to recap.hw wud (X+A)^3 look using the pattern

OpenStudy (anonymous):

could you just show me the formula then what i plug into it and where

OpenStudy (anonymous):

no.i want u to understand it. if they say (x+a)^3 then you start by writing decreasing powers of x next to increasing powers of a. so (x+a) ^3 = x^3a^0 + x^2a^1 + x^1a^2 + x^0a^3...get it?

OpenStudy (anonymous):

yes, but i will get it if i just have formula and can plug in stuff i will be able to get on with all the other questiopns

OpenStudy (anonymous):

there is no formula to get the constants in front of the terms..u have to use pascals triangle. im gana type each row of the triangle separately and il show u hw it works.

OpenStudy (anonymous):

ok

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