Question

Question: The length of a rectangle frame is 53cm for what width would the perimeter be greater than 160cm?

Answer 1

So there is two lengths of 53, so 2x53 is 106, now 160-106 is 54, now divide that by 2, since there is 2 widths, you get 27cm

Answer 2

\[2L+2W >160\]
\[2(53)+2W >160\]
\[106+2W >160 \rightarrow 2W >54 \rightarrow w >27\]
Its when the width is greater than But not equal to 27

Answer 3

Assuming that this is a 2D shape, and if x is the width and y is the length:

Perimeter \[= 2x + 2y\]
So...
\[2x + 2(53cm) > 160cm\] Multiply 2 x 53
\[2x + 106cm > 160cm\] Subtract 106 from 160
\[2x > 54cm\] Divide by 2
\[x > 27cm\]

Answer 4

the answer 82.5