Question

2/8i=?

Answer 1

Multiply BOTH numerator and denominator by i to get

(2/8i)(i/i) = (2i)/(-8) = -i/4

Note: i*i = i^2 = -1

Answer 2

what is formular you use?

Answer 3

Basically I want the denominator to be a real number. So I want to get rid of that i term. To do that, I multiply by i (since i*i = i^2 = -1, which is real). I must do the same to the numerator as well. Hopefully that clears things up.

Answer 4

ok thanks

Answer 5

but i don't understand how u have -8?

Answer 6

u still there?