whats the hospital rule for ln 3x
is it 1/3?
drink plenty of fluids, stay out of the sun
lol thanks i havent been out too extremely hot
ahaha. Do you men l'Hospitals rule? Is this supposed to be the limit as x->infinity of ln(3/x)
i have this here: lim x→ ln 3x 3x
x approaches infinity ln3x/\[\sqrt{3x}\]
so i dont know how i would compute that
\[\lim_{x\rightarrow\infty}\frac{\ln(3x)}{\sqrt{3x}}\]
is that it?
if so use no rule. get 0 from your eyeballs. log grows very slow, much slower than \[\sqrt{x}\]
yes
you are of course welcome to use l'hopital if you like
get \[\frac{1}{x}\times \frac{2\sqrt{x}}{3}\] and then get \[\frac{2}{3\sqrt{x}}\] take the limit, get 0
ok so thats the final answers?
clear yes? derivative of \[\ln(3x)\] is \[\frac{1}{x}\] and derivative of \[\sqrt{3x}\] is \[\frac{3}{2\sqrt{x}}\]
yes answer is 0
yes thanks!
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