Find the equation in point-slope form passing through the points (3, -12) and (-4,2).

Question

jim_thompson5910 · Answer

First find the slope

m = (2-(-12))/(-4-3) = 14/(-7) = -2

So m = -2

Now plug x=3, y = -12 and m=-2 into the equation

y - y1 = m(x-x1) 

to get


y-(-12) = -2(x-3)

and simplify

y + 12 = -2(x-3)

radar · Answer

Since you were given two points you can use the:
        y2 - y1
m = ---------
        x2-x1

m=(2-(-12))/(-4-(3))=14/-7=-2  slope is -2 or m=-1

It appears that jim_thompson beat me to the finish. lol

anonymous · Answer

12 + y = -2(x + -3)

Reorder the terms:
12 + y = -2(-3 + x)
12 + y = (-3 * -2 + x * -2)
12 + y = (6 + -2x)

radar · Answer

The equation is normally placed in the form of:
y=-2x-6  (slope intercept form
2x+y+6=0  standard form

anonymous · Answer

ok i think i get it

radar · Answer

Standard form may also be: 2x+y=-6