Question

when 8 consecutive integers are multiplied, their product is 0. What would be their largest possible sum?

Answer 1

28

Answer 2

we have x*(x+1)*(x+2)*(x+3)*(x+4)*(x+5)*(x+6)*(x+7)=0
these are 8 consecutive numbers whose product is 0
that means one of these have to be 0 in order for the product to be 0
and since we want the largest possible sum we say x=0
so x+1=0+1=1
and x+2=0+2=2
...
x+7=0+7=7
so we have
0+1+2+3+4+5+6+7=? you fill in this blank

Answer 3

yes and 28 is right gj!