Question

20x-3(7x+6)<=8x+16

Answer 1

20x-3(7x+6)<-8x+16
First, we can distribute the negative 3 to the sum in parentheses:
20x-21x-18<-8x+16
Next, we can combine the like terms on the left side of the inequality:
-1x-18<-8x+16
Then, we can add 18 to both sides:


-1x<-8x+34
Afterwards, we can add 'x' to both sides of the inequality:
0<-7x+34
Then, we can add '7x' to both sides of the problem:
7x<34
Finally, we can divide both sides of the inequality by 7.
x<34/7

Answer 2

i got -34/9

Answer 3

20x-3(7x+6)<=8x+16
now see
20x - 21x - 18 = 8x + 16
-x - 18 = 8x + 16
-9x = 34
x = -34/9

Answer 4

In short You are right this time texas

Answer 5

ok

Answer 6

did u got it

Answer 7

so i think that now u have a good answer

Answer 8

yep thts exactly what i did

Answer 9

ok

Answer 10

how do i set it in builder notation

Answer 11

builder notation ?????/

Answer 12

why do u need it in builder notation

Answer 13

kush its not x = -34/9 its x<= -34/9

Answer 14

ok sorry

Answer 15

give me on second i left tthe negative off the 8 resovlin problem now

Answer 16

so if you have to write it in set builder write {x|x<=-34/9} I have not solved the eq. as you have solved it already. I just converted it into a set.