Question

suppose a,b,c are not coplanar. if d=k1(bxc)+k2(cxa)+k3(axb) where k1,k2,k3 are constants ,prove that d=[(a.d)(bxc)+(b.d)(cxa)+(c.d)(axb)]/(axb).c

Answer 1

Just Multiply and Open You'll get (axb).c after simplification common in the numerator [You cancel this with the denominator]and you'll be left with an expression of the form k1(bxc)+k2(cxa)+k3(axb).