Question

. Find the equation of a line which passes through point (-4, 5) and is parallel to the line formed by the equation y = 3x + 1. Express it in slope-intercept form.

Answer 1

since the line is parallel to y= 3x+1, it will have the same slope, so m=3
\[y-y_{0}=m(x-x_{0}), y_{0}= 5, x_{0}=-4\]
\[y-5=3(x-(-4))\rightarrow y=3(x-(-4))+5 \rightarrow y=3x+17\]

Answer 2

answer ed it already

Answer 3

in earlier posting

Answer 4

nadeem
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