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Mathematics 22 Online
OpenStudy (anonymous):

This problem has been haunting me!

OpenStudy (anonymous):

If you mean the problem you already posted, you should discuss that there.

jhonyy9 (jhonyy9):

can you write this here ?

OpenStudy (anonymous):

the problem?

jhonyy9 (jhonyy9):

no the haunter

OpenStudy (anonymous):

here is the file...

OpenStudy (anonymous):

If I get a chance and nobody else helped u in the meantime, I will try and look at the document a bit later.

OpenStudy (anonymous):

Thank you very much estudier!

OpenStudy (anonymous):

I really only need an answer for Part I

OpenStudy (anonymous):

I guess the most straightforward one to do is a Royal Flush because obviously there are only 4 of them out of all the possible hands. All the possible hands is given by 52! and to choose 5 you want 5/52 * 4/51 * 3/50 * 2/49 *1/48 = 5! 47!/52! = 1/2,598,960. There are only 4 royal flushes so multiply by 4 = 1/649,740. That do?

OpenStudy (anonymous):

I'm trying to understand how it's calculated. I'm sure your answer is correct, but see in the word doc where the prof. gives an example explanation?

OpenStudy (anonymous):

What explanation would accompany your answer?

OpenStudy (anonymous):

U mean the stuff in brackets?

OpenStudy (anonymous):

The probability, I believe, is supposed to be a percentage

OpenStudy (anonymous):

For a percentage just multiply by a 100.

OpenStudy (anonymous):

I see your fractions, so that's the calculation - but then the prof. wants an explanation, look below the stuff in brackets

OpenStudy (anonymous):

Don't get it, for a Royal Flush it's just 52 Choose 5. If you want more of an explanation then the first card must be 1 of AKQJ10 of a suit out of 52 cards, the second has to be one of the remaining 4 out of the 51 left...etc.

OpenStudy (anonymous):

Don't get it, for a Royal Flush it's just 52 Choose 5. Then, for a particular Royal Flush *4.

OpenStudy (anonymous):

So let me see if I understand..

OpenStudy (anonymous):

Royal Flush 5/52 times 4/51 times 3/50 times 2/49 times 1/48 = 5

OpenStudy (anonymous):

? (5*4*3*2*1)/(52*51*50*49*48) which is what I already put ie 5/52 * 4/51 * 3/50 * 2/49 *1/48 = 5! 47!/52! = 1/2,598,960.

OpenStudy (anonymous):

As you can see the probabilty is very low...

OpenStudy (anonymous):

Where I'm getting confused is here: = 5! 47!/52! = 1/2,598,960 It says "=5" then it has another fraction after that, 47/52, where does that and "= 1/2,598,960" come from?

OpenStudy (anonymous):

I'm a math idiot, so I apologize

OpenStudy (anonymous):

It doesn't say 5, it says 5! which is short for 5*4*3*2*1. n! means n*(n-1)*(n-2)........*1

OpenStudy (anonymous):

The prof. hasn't used the exclamation points with us, that's what's confusing me

OpenStudy (anonymous):

5! 47!/52! is the same as 52 choose 5 (ie 52 above 5 in brackets like in your paper) 47! in the top cancels with 47 and all the numbers below it in the bottom leaving you with 5/52 * 4/51 * 3/50 * 2/49 *1/48 If you don't know this notation then your professor won't expect u to use it, just write it out the long way.

OpenStudy (anonymous):

So I should write it like this:

OpenStudy (anonymous):

God this makes me nervous

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

I like English ;)

OpenStudy (anonymous):

You know what? I'm still lost. It's not your explanation. I just can't wrap my head around these kinds of things. I can't figure out how to write it out the long way, why we "choose 5" if there are only 4 RF's possible. I'm just lost.

OpenStudy (anonymous):

Because there are 5 cards in a hand.

OpenStudy (anonymous):

You are "choosing" 5 cards from 52 cards not 4 royal flushes

OpenStudy (anonymous):

Like the example in your paper, u choose cards not pairs.

OpenStudy (anonymous):

The question is whether u can make a pair with the cards you choose (or a Royal Flush).

OpenStudy (anonymous):

So I'm choosing my first card from a deck of 52, my 2nd card from a deck of 51, 3rd from a deck of 50...

OpenStudy (anonymous):

And how many times does that happen out of all the possible times.

OpenStudy (anonymous):

Yes, correct.

OpenStudy (anonymous):

so the "5, 4, 3,..." are not actual numbers, but your representation of each card

OpenStudy (anonymous):

Not exactly, in order to get a particular Royal Flush, in Hearts, say, there are 5 cards in the deck that make up that Royal Flush. So I have to get 1 of them on the first deal, another on the next when there are 4 remaining of 51, etc. What I don't understand is why you are querying the calculation, I am doing it in the same way as your example eg in your paper you have 12 choose 3 for the pair example. Don't u know what it means?

OpenStudy (anonymous):

Not really. Match confuses me all around. I'm SURE you're right, I would just like to understand it for myself

OpenStudy (anonymous):

*Math

OpenStudy (anonymous):

I agree with your desire but it seems to me u are asking some very basic questions that suggest to me u need a lot more study before tackling questions like this. It's not just formulas that you can plug things into, u need to think a bit about what is actually going on.

OpenStudy (anonymous):

Well here's what I have...

OpenStudy (anonymous):

so far, based on what you've said

OpenStudy (anonymous):

I chose Royal Flush because obviously there are only 4 of them out of all the possible hands. The number of possible hands is represented by “52”. To choose 5 cards we use the equation: 5/52 * 4/51 * 3/50 * 2/49 * 1/48 There are 5 cards in the deck that make up the Royal Flush. So I have to get 1 of them on the first deal, another on the next when there are 4 remaining of 51, etc. The above equation comes out to: 5*4*3*2*1 / 52*51*50*49*48 There are 47 cards left in the deck after the 5 cards are chosen.

OpenStudy (anonymous):

correct so far?

OpenStudy (anonymous):

Let me read it...

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

I chose Royal Flush because obviously (delete put since) there are only 4 of them out of all the possible hands. The number of possible hands is represented by “52” (meaning 52*51*50*...*1) (The probability) To choose (the) 5 cards (that make up a particular (one of the 4)Royal Flush,) we (calculate as follows) use the equation (it's not an equation) : 5/52 * 4/51 * 3/50 * 2/49 * 1/48 There are 5 cards in the deck that make up the (a particular) Royal Flush. So I have to get 1 of them on the first deal, another on the next when there are 4 remaining of 51, etc. The above equation comes out to: 5*4*3*2*1 / 52*51*50*49*48 (you already said this) There are 47 cards left in the deck after the 5 cards are chosen.

OpenStudy (anonymous):

You could also delete the last sentence.

OpenStudy (anonymous):

So what u have written covers getting a Royal Flush but there 4 of them out of the total so you need to multiply by 4.

OpenStudy (anonymous):

Thanks! So how could we finish it off, in the same explanatory fashion, using the rest of your calculation

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Well, to be honest I think it is not my work to write your assignment for u... You should do it in your own words. I have given u all the information u need to do it by yourself.

OpenStudy (anonymous):

i don't think you should either, I just want to make sure that what I'm saying makes sense

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

I'm trying to write it out now

OpenStudy (anonymous):

Well, u saw my corrections to your first attempt.... I think u need to sit down and think about this problem a bit more carefully before u write anything. You have the "answer" it is now a question of explaining why that is the answer.

OpenStudy (anonymous):

On reflection, it might be a good idea to use ! notation as it will demonstrate that u have researched/learned something (provided u understand it, that is).

OpenStudy (anonymous):

The above calculation results in: 5*4*3*2*1 / 52*51*50*49*48, which equals 1/2,598,960 (3.84769292 * 10-7). There are only 4 royal flushes, so we multiply by 4 and get 1/649,740 (1.53907717 × 10-6).

OpenStudy (anonymous):

decimals look right?

OpenStudy (anonymous):

it's 10 to the negative 7 power, not 10-7

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