Rationalize the Denominator: 3x/√5:(x^(2)yz^(4))
what does the colon represent?
Ugh i formated it on the front page, it should be the fith root of x^2yz^4
\[\sqrt[5]{x^2yz^4}\]
ah ok, well the first rule of these equations is to get rid of the radical in the denominator
Ok, by mutliplying into the denom?
since it is the fifth route, you need to multiply until each variable has a factor of 5 as an exponent
So, x10y5z20?
ah ok, well the first rule of these equations is to get rid of the radical in the denominator
What about the x by the three?
Oh ok. Sorry im a bit laggy
\[\sqrt[5]{x ^{3}y ^{4}z}\]
if you multiply that to the denominator you will get \[\sqrt[5]{x ^{5}y ^{5}z ^{5}}\] or xyz
Im confused?
\[3x/\sqrt[5]{x ^{2}yz ^{3}} \times \sqrt[5]{x ^{3}y ^{4}z} / \sqrt[5]{x ^{3}y ^{4}z}\]
then it becomes \[(3x \sqrt[5]{x ^{3}y ^{4}z}) / xyz \]
The z is to the four not the y
ok, im sorry for the confusion, this is my first time trying this
is this problem, you have a radical in the denominator, to get rid of that you must make each exponent underneath the radical 5
that way the exponent and the radical cancel out
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