Question

Given the quadratic function f(x)=x^2-6x+9, find a value of x such that f(x)=25. Show all work, please.

Answer 1

x^2-6x+9 = 25

solve.

Answer 2

x^2 -6x -16

Answer 3

Solve thsi!

Answer 4

this*

Answer 5

what goes into -6 that goes into -16. I have nothing other than 1 and -16

Answer 6

I have (x + )(x- )

Answer 7

f(x) = 25 means x² - 6x + 9 = 25
x² - 6x + 9 - 25 = 0
x² - 6x - 16 = 0
x² -8x + 2x - 16 = 0
x(x - 8) + 2(x - 8) = 0
(x + 2)(x - 8) = 0
this is possible if either x+2 = 0 or x-8 = 0
if x + 2 = 0 ==> x = -2
if x - 8 = 0 ==> x = 8


so f(x) = 25 for x = -2 and x = 8

Answer 8

Hakirat, is 100% corrct.

Answer 9

thanks saifoo :D