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When solving for a in -8+square route of (5a-5)=-3, do I square -8 when i get rid of the square route, and if so does it become 64 or -64?
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add 8 first!
otherwise you will have a mess. \[-8+\sqrt{3a-5}=-3\] \[\sqrt{3a-5}=5\] etc
first add 8, then square, then solve
oh thanks i completely forgot about adding the 8!
then check
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oh damn ignore my answer. i used \[3a-5\] instead of \[5a-5\] sorry
that's fine i can solve it now that i know to add the 8. thanks!
\[\sqrt{5a-5}=5\] \[5a-5=25\] \[5a=30\] \[a=6\] is more like it
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