for principal quantum number n=4 write down the available azimuthal angular moment quantum numbers (l) and the magnetic quantum numbers (m). describe each value of l in terms of an orbital symbol (eg 3s) and calculate the number of electrons that can be accommodated in each site.

Question

anonymous · Answer

l will be 0,1,2,3
ml will range from -3 to 3 including 0.
0 = 1s = 2 electrons
1 = 2s2p = 8 electrons
2 = 3s3p = 8 electrons
3 = 4s4p3d = 18 electrons

The questions not so clear so I'm not sure if this is what it's looking for.

anonymous · Answer

thanks so much!!

anonymous · Answer

To further the above, to calculate the number of electrons allowed in each level you use the formula $$N=2(2l+1)$$hence for s shells (l=0) you can have 2 electrons, for p shell (l=1) N=6, d shell (l=2) so N = 10, and f shell (l=3), N=14. Remember that the progression goes $1s^22s^22p^63s^23p^6...$ following teh aufbau principle http://en.wikipedia.org/wiki/Aufbau_principle