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Mathematics 16 Online
OpenStudy (anonymous):

use the given zero to find the remaining zeros of the function: f(x)= x^4-12x^2-64; zero:-2i please show me step by step... thanks..

OpenStudy (amistre64):

hmm, is that spose to be an imaginary number?

OpenStudy (anonymous):

(x+2i)(x-2i) because they come in conjugates: x^2+ 4 and divide the original by x^2+4

OpenStudy (amistre64):

if so, x^4 indicates that the zeros are located 90 degrees from each other i think

OpenStudy (amistre64):

-2i, 2, 2i, and -2 would be it if I see it right

OpenStudy (anonymous):

so i got x^2-16 so itd be +/- 4

OpenStudy (amistre64):

http://www.wolframalpha.com/input/?i=x^4-12x^2-64

OpenStudy (anonymous):

oh wait no youre right

OpenStudy (anonymous):

no i am right

OpenStudy (amistre64):

the way i remember complex zeroes is that the highest degree tell us how to divide the circle; x^2 would be 360/2 x^3 would be 360/3 x^4 would be 360/4 = 90 since -2i is the same as 270 degrees; we end up on the axises each time

OpenStudy (anonymous):

it would be +/- 2i and +/- 4

OpenStudy (amistre64):

thats it :)

OpenStudy (anonymous):

i still dont understand... :(...

OpenStudy (amistre64):

how much of it do you understand tho? so we have something to work from

OpenStudy (anonymous):

when you have imaginary zeros, they always come in conjugate pairs such as x+i x-i so you can multiply those together to get a factor. so then you can divide the original polynomial by that factor

OpenStudy (anonymous):

not factor... another polynomial. bad wording haha

OpenStudy (anonymous):

hihi ok.

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