Identify the local maximum value for the function f (x) = x^6 - 6x^4 + 5, using the first derivative test.
what do you get for the derivative?
6x^5-24x^3
similar to last one yes? take the derivative. factor. find the zeros. check the sign
is that right?
thats good
it is cooked up to factor easily. and so easy to find the zeros yes it is right. factor now
now to zero it out factor out what it has in common
Ummm.. Im not sure how to do it but ill give it a shot.. :/ 6(x^5-4x^3). Is that right?
Is this correct or am I wrong?
can factor out a lot more than that. as in previous example
i'll give you a hint. it is \[6x^3(x^2-4)\]
okay. I got this far with your help.. I have no clue as to how to go to the next step
set the derivative = 0 and solve
you will get 3 zeros. name them
\[6x^{3}\ +(x^{2}-4) = 0\]
hello? pleae dont make me sad :(
6x^5 -24x^3 ; factor out the 6 and the x^3 6x^3 (x^2 - 4) = 0 ; we can factor it again or just realize the +- 2 give the same results so when x = -2, 0, 2 we have critical points
6x^3 (x-2) (x+2) when we plug in a -3 we get; -.-.- = - when we plug in a -1 we get; -.-.+ = + when we plug in a 1 we get; +.-.+ = - when we plug in a 3 we get; +.+.+ = + <.........-2..........0...........2.........> - + - + ride this like a roller coaster now, from left to right at -2 we go down then up, thats a minimum at 0 we go up then down; that a maximum at 2 we go down then up; that a minimum. http://www.wolframalpha.com/input/?i=x^6+-+6x^4+%2B+5
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