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Find f ''(x) when f(x)=sinx/ x^2. Thanks
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i suggest graphing it to get your 0s
I dont know how to do that though.
:/ Pleasee help me with this. Ive been working on this problem for like an hour and I still can't get it. Ugh im so confused
Rewrite this as \[\sin(x) \times x^{-2}\] Then use the rule of taking the 1st times the derivative of the 2nd plus the 2nd times the derivative of the first. (1D2 + 2D1 is what I like to remember it by). \[\sin(x)(-2x ^{-3)}+(x ^{-2})(-\cos(x))\] is the first derivative. Do the same for the second derivative now using the 1D2 + 2D1 rule for both terms.
WHATTT?! please break it down more for me! :/
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got it!
You sure? :)
yuppp :D You helped me alot! you're the best <3
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