Question

can you not only give me the answer to this problem but show me how you got it please i really am confused. In figure below, R is the midpoint of NP. If the circumference of circle N is 75.36, what is the area of circle P?

Answer 1

What's the question?

Answer 2

In figure below, R is the midpoint of NP. If the circumference of circle N is 75.36, what is the area of circle P?

Answer 3

First get the larger radius NP:
\[75.36=2\pi r _{1}\]
\[r _{1}=75.36/(2\pi)\]
Since R is the midpoint the radius of the smaller circle is half the bigger radius:
\[r _{2}=0.5r_{1}\]
\[r _{2}=75.36/(4\pi)\]
Area of the smaller circle:
\[Area = \pi r_{2}^{2}\]
\[Area = \pi(75.36/(4\pi))^{2}=\pi(5679.1296/(16\pi^{2}))=(5679.1296/16\pi)=112.98\]

Answer 4

That took a few to type up :)

Answer 5

thnk you so much =)

Answer 6

No problem. Happy to help. My chem final is past so my brain is freer to focus on stuff like this ;)