Question

A number added to 8 times that numbers recipricol is 6, find the number
a 3 b 2 c 7 d 14

Answer 1

Call your unknown number x. The reciprocal would be
\[\frac{1}{x}\]You are supposed to add your unknown number to 8 times its reciprocal, or
\[x+8(\frac{1}{x})\]This is all supposed to equal 6, so you have
\[x+\frac{8}{x}=6\]
Solve for x to get your number.

Answer 2

n + 8(1/n) = 6
n^2 + 8 = 6n
n^2 - 6n + 8 = 0
(n - 4)(n - 2) = 0
n = 2, 4

Answer 3

is 2 its answer ??????

Answer 4

Out of the choices given, yes. However, 4 is also a solution.

Answer 5

2 and 4 are answers thank you

Answer 6

L^2+8=6L
L^2-6L+8=0
L=2,4