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if sin0 = 1/radical2, find the value of 0 a. 30º b. 45º c. 60º d. 90º
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45
ignore the 6 and 7 just the same triangle though
how do you know?
well because i have the 45, 45, 90 triangle memorized. hypotenuse is 1, both sides are \[\frac{\sqrt{2}}{2}\]
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we can derive it if you like
ok thank you!
wait,
make a 45 45 90 triangle. because to angles are the same, so are the two legs. make the hypotenuse 1 and call the sides x then \[x^2+x^2=1\] \[2x^2=1\] \[x^2=\frac{1}{2}\] \[x=\frac{1}{\sqrt{2}}\]
nevermind you are right, the 2 legs are equal
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whew
thank you!i gave you a medal for your help!
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