Question

solve: tanx+cotx=2.

Answer 1

Range pls

Answer 2

sinx.cosx=1/2

Answer 3

whts dis???????

Answer 4

Since u have not given me any range,I have simply simplified it

Answer 5

bt ur's wrong!!

Answer 6

let y = tanx
then because:
\[\cot(x) = \frac{1}{\tan(x)}\]
Your equation becomes:
\[y+\frac{1}{y} = 2\]
By inspection, the solution to this is y = 1.
So now we have:
\[y = 1 \Rightarrow \tan(x) = 1 \Rightarrow x = \frac{\pi}{4}, \frac{5\pi}{4}\]

Answer 7

by joemath314159265's answer
y+1/y=2
y\[^{2}\]-2y+1=0
y=(2\[\pm \sqrt{4-4}\])/2
y=1
ie tan x=1;
the eqn has infinite no of solutions
the principal solns r x=\[\Pi\]/4