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There are two consecutive odd numbers such that twice the smaller number plus one is ten more than the greater number. What is the smaller number? 7 9 11 13
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\[2*7=14\] no, since 14 is not ten more than 9
\[2\times 9=18\] nope
\[2\times 11=22\]
a,b is the number for odd number is 2n-1 a is 2n-1 and b is 2(n+1)-1 2a+1=10+b so n=6 hence a=11 b=13
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add 1 get 23. so that is the one!
so 11
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