Question

Write the equation of the line that passes through (1, 3) and (4, 4) in standard form.

Answer 1

\[m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-3}{4-1}=\frac{1}{3}\]
\[y-4=\frac{1}{3}(x-4)\]
\[y-4=\frac{1}{3}x-\frac{4}{3}\]
\[y=\frac{1}{x}x+\frac{8}{3}\]

Answer 2

First find the slope of the two equations by plugging them in:

(y2 -y1)/ (x2-x1)

(1,3) = (x1, y1)
(4, 4) = (x2, y2)

Solve and you should the slope or m in the equation y = mx + b

Then plug the "m" value in the equation:

y - y1) = m (x - x1)

This time, pick any of the two coordinates provided as being (x1, y1) Doesnt matter which one..
Solve and you should get your standard equation =)

Answer 3

so the equation is y-3=1/3 (x-1)

then how would you solve that?
I know you have to add 3 to both sides first

Answer 4

y-y1/y2-y1=x-x1/x2-x1
y-3/4-3=x-1/4-1
y-3/1=x-1/3
3(y-3)=1(x-1)
3y-9=x-1
x-3y+9-1
x-3y+8=0
this is the eqaation of two points

Answer 5

okay i got it now! thanks alot! everythings right execpt its - 8 instead of +8 :)