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Find a fourth-degree polynomial that has the indicated zeros: _ _ -2/5 (multiplicity 2), 3+/2, and 3-/2.
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\[(5x+2)^2\] is one factor. that makes \[-\frac{2}{5}\] a zero with multiplicity 2
the other factor is \[(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))\] so you have to multiply that out, which is easier than it looks. can you do it?
\[x^2-6x+7\]
?right?
yes!
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so now if you need to you have to multiply \[(x^2-6x+7)(5x+2)^2\] to put in standard form. if you need to
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