synthetic division: (x ^3 - 5x^ 2 + 4x + 7 ) ÷ (x - 1)
can you show me how? :(
this is essentially the same as the other question you asked, but with a little difference, i'll show how to do it below: ______________________________ x-1 | x^3-5x^2+4x+7 step 1: We multiply by x^2 because we want to negate that first term, and since x * x^2 =x^3 that's what we are going to go with. x^2 ______________________________ x-1 | x^3-5x^2+4x+7 - x^3-x^2 ___________ -6x^2+4x Step 2: now since we have gotten rid of the first term, we now want to negate the second. so since x * -6x = -6x^2, that's what we are going to use. x^2-6x ______________________________ x-1 | x^3-5x^2+4x+7 - x^3-x^2 ___________ -6x^2+4x -(-6x^2)+6x ______________ 10x+7 Step 3: now we want to deal with the 10x that we have there. however, we cant have a negative remainder, so we have to use the most that we can. since we are limited by the 7, that is what we are going to use, since we must use our whole term. x^2 -6x +7 ______________________________ x-1 | x^3-5x^2+4x+7 - x^3-x^2 ___________ -6x^2+4x -(-6x^2)+6x ______________ 10x+7 - 7x -7 ________ 3x since we have used all we can, we will write our answer: x^2 -6x +7 remainder 3x
it says thats wrong though?
Divide the following polynomial using synthetic division, then place the answer in the proper location on the grid. Write answer in descending powers of x. (x ^3 - 5x^ 2 + 4x + 7 ) ÷ (x - 1)
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