Which of the following is the correct equation for this function? it shows a graph with a parabola facing upwards with a vertex of (-3,-2) and the x intercept of (-2,0) and (-4,0) A. y=x^2+3x-2 B. y=2=-2(x+3)^2 C. y=(x+4)(x+2) D. y+2=2(x+3)^2
option B looks invalid - can you check it please?
ph my bad its supposed to be y+2=-2(x+3)^2
D
thanks just wondering how did you get that answer so i know how to do it in future
Substitute x = -2 in to the equation and you get y = 0. Substitute x = -4 in to the equation and you get y = 0 So it has x intercept of (-2,0) and (-4,0)
But this is not the only one of the options for which this is true so we need to check the vertex as well
so you need to simplify the function, expanding out the brackets, and get it in the form of y = ...... which is y= 2x^2+12x+16
differentiate this to get dy/dx = 4x + 12 At the vertex, dy/dx = 0 so 4x + 12 = 0 so 4x = -12 so x = -3
Sub this in to y= 2x^2+12x+16 to get y = -2 so the vertex is -3, -2) D fulfils all conditions specified so its the answer!
cool thanks alot! :)
you are most welcome :-) TheMathsTutor.Com
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