Question

Find dy/dx by implicit differentiation and evaluate the derivative at the given point.
tan(5x + y) = 5x

Answer 1

(5+y')sec^2(5x+y)=5

Answer 2

hey

Answer 3

sec^2(5x+y)(5+y')=5

Answer 4

these guys are beasts!

Answer 5

yeah..so imran how would you continue that

Answer 6

.....

Answer 7

I would distribute first
5sec^2(5x+y)+y'sec^2(5x+y)=5

Answer 8

This is hard to do on the iPhone lol

Answer 9

you need a medal for even trying lol

Answer 10

lol sorryy

Answer 11

\[y' \text{Sec}^2[5 x+y]+5 \text{Sec}^2[5 x+y]=5\]
\[y' \text{Sec}^2[5 x+y]=5-5 \text{Sec}^2[5 x+y]\]
\[y'=\frac{5-5 \text{Sec}^2[5 x+y]}{\text{Sec}^2[5 x+y]}\]
\[\frac{5}{\text{Sec}^2[5 x+y]}-5\]
\[-5+5\text{Cos}^2[5 x+y]\]
\[-5+5\left(1-\text{Sin}^2[5x+y]\right)\]
\[y'=-5 \text{Sin}^2[5 x+y]\]