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Mathematics 22 Online
OpenStudy (anonymous):

3sqrt(x)/14-sqrt(x) I need the answer with steps. I keep getting 3(14sqrt(x)+x/-x+196.

OpenStudy (anonymous):

Is (14-sqrt x) the denominator?

OpenStudy (anonymous):

multiply top and bottom of fraction by the conjugate of 14-sqrt(x) which is 14+sqrt(x)

OpenStudy (anonymous):

If so, do waht jimmyrep said.

OpenStudy (anonymous):

yes ok let me try I pretty sure that's what im doing

OpenStudy (anonymous):

It should come out to the third of the alternate forms here: http://www.wolframalpha.com/input/?i=%283sqrt%28x%29%29%2F%2814-sqrt%28x%29%29

OpenStudy (anonymous):

keeps saying it wrong I dont get it!

OpenStudy (anonymous):

mine is coming exactly in the third alternate form

OpenStudy (anonymous):

right but when I enter it in to math lab it saying its wrong every way i enter it

OpenStudy (anonymous):

i make it 3(14sqrtx + x) / (196-x)

OpenStudy (anonymous):

Have you tried entering the top as 42 sqrt x + 3x ?

OpenStudy (anonymous):

strange - but rest assured our answer is correct

OpenStudy (anonymous):

i think math lab got this one wrong everyone It had the hole problem flipped and it was calling it right.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

here is my next problem 6sqrt(x)/5-sqrt(x)

OpenStudy (anonymous):

Everyone gets medals for determining that mathlab is an retrice

OpenStudy (anonymous):

solve it the same way. multiply it by 5+ sqrt(x)

OpenStudy (anonymous):

same method fr this - use 5 + sqrt x

OpenStudy (anonymous):

U should post that as a new question even if u do it exactly the same way...

OpenStudy (anonymous):

o ok sorry

OpenStudy (anonymous):

Just that the thread gets a bit confusing for others...

OpenStudy (anonymous):

understand should i repost it now?

OpenStudy (anonymous):

Sure go ahead, u will get an answer pronto. But u know how to do it now, anyway, don't u?

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i dnt understand this question any body expalin me

OpenStudy (anonymous):

Which part?

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