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Solve the exponential equation using the method of relating the bases by first rewriting the equation b^u=b^v 6^x2/36^x=216
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well, 6^3 = 216, i remember that from a test I took a long time ago for some reason
:-)
so (-1,3)?
yep
6^(x^2) ------- = 6^3 ; unless I see it wrong, this is saying that 1 = 216 (6^2)^x)
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crud, it says (-1,3) isn't right
really? 6^(x^2)/(36^x)=216 => 6^(x^2-2x)=216 => x = -1 or x = 3. is the problem written correctly?
\[6^{x2} \div36^x=216\]
http://www.wolframalpha.com/input/?i=6^%28x^2%29%2F36^x+-+216 tehm is correct, but if your working with a program its prolly wanting a specific format
thanks, I formatted the answer wrong. doh! You had the right one.
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:) i loathe working with programs ....
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