Question

how do i solve d/dx 20log(4x)+1000x^2

Answer 1

by deriving id assume :)

Answer 2

the complicated issue is in recalling how to deal with the log(x)

Answer 3

agree. is it 20/x? but what happens to 4x?

Answer 4

ln(x) derives down to 1/x; so lets translate that log into lns

Answer 5

log(4x) = ln(4x)/ln(10) by change of base right?

Answer 6

http://www.wolframalpha.com/input/?i=d%2Fdx20log%284x%29%2B1000x^2
click "show steps"

Answer 7

ln(10) is a constant so it can be pulled out;

ln(4x) becomes 1/4x and the chain rule pops out a 4 to get:

4/4x = 1/x; bring back our straglers to get:

20/(x ln(10))

Answer 8

ok. now i get where i went wrong. thx.:)

Answer 9

youre welcome :)