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5√12-√3 ?
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Okay 12 is 4*3, so: sqrt(12)=sqrt(4*3)=sqrt(2*2*3)=2sqrt(3)
5*sqrt(12)=5*2sqrt(3) = 10sqrt(3)
10sqrt(3)-sqrt(3)=9sqrt(3)
\[10\sqrt{3}-\sqrt{3} = 9\sqrt{3}\]
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\[\sqrt{12}\] can be written as \[\sqrt{4} \times \sqrt{3}\] however, as \[\sqrt{4}\] = 2 5\[\sqrt{12}\] = 5 x 2 √3 Therefore, 10√3−√3=9√3
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