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x/3-2/9=2/5(x+17/3)
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x/3-2/9=2/5(x+17/3) \[\frac{3x-2}{9}=\frac{2}{5}*\frac{(3x+17)}{3}\] \[\frac{3x-2}{9}=\frac{6x+34}{15}\]
ok your loosing me, I am confused now
\[15(3x-2)=9(6x+34)\] \[45x-30=54x+306\] \[9x=-336\] \[x=-336/9\] \[x=-112/3\]
ok i get it now
(x/3)-(2/9) = (2x/5)+(34/15) (3x-2)/9 =(2x/5)+(34/15) 3x-2 = 9[(2x/5)+(34/15)] 3x-2 = (18x/5)+(102/5) 3x-2 = (18x+102)/5 5(3x-2) = 18x+102 15x-10 = 18x-102 15x-18x = 102+10 -3x = 112 x = 112/-3 x = -112/3
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mathematicalpro - could you explain what you did at each step please? I'm afraid I don't understand fractions well at all... I'd love to know how you worked your magic. As of right now I am SUPER CONFUSED. :/
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