factor completely a^2-10ab+3b^2 and then 5x^2-10x
man you have quite a bit of homework, lol
you dont even know :| lol
these are my last two problems though !!
I dont think the first one can be factored.
oh nice. kk - the 1st is: (a-5b)^2-22b^2 the 2nd is: 5(x-2)x
the first is not factorable 5x^2-10x 5x(x-2)
ohh complete the square thing nice tehmagik!
that first one can be factored even further: (a-5b)^2-22b^2 = [(a-5b)-bsqrt(22)][[(a-5b)+bsqrt(22)]
wait so is the first one factorable or not?
it is.
can someone show me the steps for the 2nd one i dont understand this at all lol
Okay for the 2nd one: 5x^2-10x what do u see in common in both terms?
the 5
Or what would u see if I rewrote this as: x(5x) - 2(5x)
the 5x
yes so take it out: 5x(x-2)
and then factor that or is that the answer?
That's as far as you can factor it. x-2 cannot be factored further, and neither can 5x.
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