Mathematics
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OpenStudy (anonymous):
frac{5-x}{x-2}-frac{5x-8}{2-x}
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OpenStudy (anonymous):
\[\frac{5-x}{x-2}-\frac{5x-8}{2-x}\]
OpenStudy (anonymous):
Subtract and simplify.
jimthompson5910 (jim_thompson5910):
\[\frac{5-x}{x-2}-\frac{5x-8}{2-x}\]
\[\frac{5-x}{x-2}-\frac{5x-8}{-1(x-2)}\]
\[\frac{5-x}{x-2}+\frac{5x-8}{x-2}\]
\[\frac{5-x+5x-8}{x-2}\]
\[\frac{4x-3}{x-2}\]
OpenStudy (anonymous):
Subtract and simplify.
OpenStudy (anonymous):
Thanks again!!
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OpenStudy (anonymous):
Subtract and simplify.
OpenStudy (anonymous):
\[f(x)=1/3(x+8)^{2}+1\]
Whats the vertex
Line of symmetry
Maximum/minimum value of f(x)
jimthompson5910 (jim_thompson5910):
Hint: Place in the form \[f(x)=a(x-h)^2+k\] The vertex will be (h,k) and the line of symmetry will be x = h
OpenStudy (anonymous):
would it be (64,1) and -8?
jimthompson5910 (jim_thompson5910):
You have part of it right. You said that the line of symmetry is x = -8. Since h=-8, what does that mean for the vertex?
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OpenStudy (anonymous):
-16? or 256?
jimthompson5910 (jim_thompson5910):
Remember, the vertex is (h,k)
OpenStudy (anonymous):
(-8,1)
jimthompson5910 (jim_thompson5910):
Good, you got it. That's the vertex.
OpenStudy (anonymous):
cool, so the line os symmetry would be -8
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jimthompson5910 (jim_thompson5910):
x=-8 since this is the equation of the vertical line at -8 on the x-axis
OpenStudy (anonymous):
The line of symmetry cannot be a negative can it?
jimthompson5910 (jim_thompson5910):
it can be any number
OpenStudy (anonymous):
ok would my maximum/minimum be 1 than?
jimthompson5910 (jim_thompson5910):
yes, that is correct. The max/min is 1. The max/min refers to the y coordinate of the vertex.
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OpenStudy (anonymous):
Ok thanks again and again, you are a lifesaver!!!