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Mathematics 24 Online
OpenStudy (anonymous):

need to know how to find "range"

OpenStudy (amistre64):

depends on what you mean by range; it means different things depending on how you use it

OpenStudy (amistre64):

well, it tends to mean a spread of values, but how you answer it depends on what it is your applying it to

OpenStudy (anonymous):

hang in there, i'll trry to give example

OpenStudy (anonymous):

highest value minus lower value or the possible y-values of a function

OpenStudy (anonymous):

a projectil is fired at speed of 75.2m/s at an angle of 34.5 deg above the horizontal on along flat firing range. i need to know the total horizontal distance covered, please

OpenStudy (anonymous):

any answers??

OpenStudy (anonymous):

hello, any body here??

jimthompson5910 (jim_thompson5910):

Try finding the equation that models the height as a function of time. Then solve that equation (ie find the roots) to find out where the projectile hits the ground. This will give you the horizontal distance that the projectile covers.

OpenStudy (anonymous):

you can't write the formula??

jimthompson5910 (jim_thompson5910):

In this case, the formula is \[h=x*tan(34.5)-\frac{9.8x^2}{11310.08\cos^2(34.5)}\] I suggest using a calculator to help you out.

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

if and ONLY if the initial height and the final height of the projectile are the same you can use the equation\[R=\frac {v _{i}^{2} \sin(2 \theta)} {g}\]In your case that would be\[R=\frac {(75.2m/s)^{2}\sin(69)}{9.8m/s^{2}}\]

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