Find an equation of the line having the given slope and containing the given point

m=3/4,(1,-7)

Question

Find an equation of the line having the given slope and containing the given point

m=3/4,(1,-7)

anonymous · Answer

y = 3/4x - 7

anonymous · Answer

incorrect

anonymous · Answer

y=0.75*x - 7.75

anonymous · Answer

plug the numbers you have into the point slope equation and the n evluate: y-y1=m(x-x1)

anonymous · Answer

Oh, crap, sorry P; Whoops. Forgot you had to plug it into point slope and then switch over.

jim_thompson5910 · Answer

$$y=\frac{3}{4}x-\frac{31}{4}$$

radar · Answer

The slope intercept form of a line equation is:  y=mx+b, where m=slope, and b=y intercept.

In your problem, the slope is given as 3/4, you can now use the formula as provided by LagrangeSon678 because you have been provided a point (1,-7)

3/4=y-(-7)/x-1)

cross multiply getting: 3(x-1)=4(y+7)
3x-3=4y+28
4y=3x-28-3
4y=3x-31
y= (3/4)(x)-31/4

to verify this answer substitute 1 for x and solve for y   should come out as a -7