find an equation of the line containing the given pair of points (-2,-1) and (-5,-3)
remember the slope formula?
Answer is \[y=\frac{2}{3}x+\frac{1}{3}\] See attachment for how I got that answer.
It said incorrect
what form do they want the equation in?
y=mx+b using integers or fractions
how are you entering the answer. Hopefully using an equation editor
it has one built in
well what I have is the right answer. I double checked to make sure
ok and you're using it?
a lot of the times, the computer is really really picky about how you enter the answer
no, you are right, I was on the wrong question
k cool
{1/6,-1/3} and {5/6,3} thats the one I am on
Answer is \[y=5x-\frac{7}{6}\] See attached as for how I got that answer.
Let me know how it works out
I know this is probably completely overwhelming, but just go over these attachments till you get it. Don't worry, just take it at your pace and you'll do fine.
How about (-1,-7) and (-6,-4)
Answer is \[y=-\frac{3}{5}x-\frac{38}{5}\] Again, see image attachment for the work shown.
write an equation of the line containing the given point and parallel to the given line. express your answer in the form y=mx+b (8,9);x+8y=3
x+8y=C 8+8(9)=C 8+72=C 80=C So the equation is x+8y=80. Now solve for y x+8y=80 8y=-x+80 y=-1/8x+10 Answer: \[y=-\frac{1}{8}x+10\]
you are the man!
great, just study over all that we went over and you'll be fine. Glad to have helped out.
Join our real-time social learning platform and learn together with your friends!