Question

does anyone know the area between the curves y=(x^2)-x and y=x^3-4x^2+3x

Answer 1

what about it?

Answer 2

http://www.wolframalpha.com/input/?i=y%3D%28x^2%29-x+and+y%3Dx^3-4x^2%2B3x

Answer 3

like whats the area when refering to calculus

Answer 4

the area will be the integral from 0 to 1 of (x^3-4x^2+3x)-(x^2-x) dx

Answer 5

that's actually a really fun integral so i'm gonna compute it for you. lol.

\[\int\limits_{0}^{1}(x^3-4x^2+3x)-(x^2-x)dx
\] \[= x^4/4-4x^3/3+3x^2/2-x^3/3+x^2/2\]

now evaluate from 0 to 1

Answer 6

there is one more integral...they cross twice

http://alturl.com/kg6eh

Answer 7

thanks