does anyone know the area between the curves y=(x^2)-x and y=x^3-4x^2+3x

Question

myininaya · Answer

so the intersect at three different points x=0, x=1,x=4
so now between 0 and 1 find out what function is higher and btw 1 and 4 also
we will use 0,1,4 as our limits when integrating

myininaya · Answer

$$\int\limits_{0}^{1}[(x^3-4x^2+3x)-(x^2-x)]dx+\int\limits_{1}^{4}[(x^2-x)-(x^3-4x^2+3x)]dx$$

anonymous · Answer

kk that makes total sense thanks. btw i just have a question is there a specified name for this type of process, like a double integral?

myininaya · Answer

the process i thought was called find the area between two curves

anonymous · Answer

yeah nvm  thats right its area between two curves

anonymous · Answer

also is it necessary to use two integrals or can it be solved with just one. is it possible?

myininaya · Answer

the way i solved would be what i have above