Question

x(squared)-x-5= 0
x=?

Answer 1

use the quadratic formula

Answer 2

Your equation is in form \[ax^2+bx+c=0\]
your equation is\[x^2-x-5=0\]
or\[1\times x^2-1 \times x -5=0\]
So you can see that coefficients for your equation is

a=1, b=-1, c=-5

then you can find the roots using this formula:
\[x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-1)\pm \sqrt{{(-1)^2}-4\times 1 \times (-5)}}{2\times 1}=\frac{1\pm \sqrt{21}}{2}\]
\[x_{1}=\frac{1+\sqrt{21}}{2}\]
\[x_2=\frac{1-\sqrt{21}}{2}\]

Answer 3

thank you, I think I forgot to set these over 2!