Question

What is the equation of the line passing through (–3, –9) and parallel to the line y = x + 6 in standard form?
plss help

Answer 1

the equation will have the same slope, therefore use \[y-y_1 = m(x-x_1) \] Replace m with 1 and replace x1 and y1 with the given point into the equation, then simplify.

Answer 2

Let me know what you get

Answer 3

uhhh idkk im so confusedddd :(

Answer 4

y - (-9) = 1(x - (-3))

Answer 5

Are you still confused?

Answer 6

um kindaa

Answer 7

What exactly are you confused about?

Answer 8

wait would it be y+9=x+3?

Answer 9

yes...then just put it in terms of y

Answer 10

what do u mean?

Answer 11

When they say "put an equation in terms of y", it simply means to "solve for y".

Answer 12

oh so y=x-6?

Answer 13

but thats not any of the options
x + y = –6

x – y = –6

x – y = 6

x + y = 6 see

Answer 14

?

Answer 15

well, what you do is, just simply subtract 6 from both sides, then subtract x from both sides....see what you get afterwards...

Answer 16

This is kind of tricky....you'll have to do a bit of algebra to get it right

Answer 17

You started out with y +9 = x + 3

if you subtract 9 from both sides, you get y = x -6

If you subtract x from both sides, you get y - x = -6

Now, switch the x and y: -x + y = -6

Now factor -1 from -x + y: -(x -y) = -6

Now divide both sides by -1: x - y = 6

So the final answer is: x - y = 6

Answer 18

idk.