What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form?
please help me i have 2 minutes to turn this answer in :(

Question

anonymous · Answer

First find the slope of the perpendicular line. It is the negative reciprocal of the original slope. 

What is the slope of your starting line?

anonymous · Answer

thats all it gives me and these are the possible answers: 
y = –3x – 6
		
y = negative one-thirdx – 5
		
y = 3x + 4
		
y = one-thirdx + 3

anonymous · Answer

I'm not asking what it gives you. I'm asking you to look at the equation of the line, in the form y = mx+b,   where m is the slope and b is the intercept, and tell me what the slope is.

anonymous · Answer

m is the slope and its -3

anonymous · Answer

Right, so if m is the slope, the negative reciprocal is $-\frac{1}{m}$

So in this case we have $-\frac{1}{-3}$ which simplifies to just?